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计算机等级考试二级VB算法(4):进制转化

2009-02-28

1、算法说明 1)        十进制正整数m转换为R(2-16)进制的字符串。          思路: 将m不断除r取余数,直到商为0,将余数反序即

1、算法说明

1) 十进制正整数m转换为R(2-16)进制的字符串。
思路: 将m不断除r取余数,直到商为0,将余数反序即得到结果。
算法实现:
Private Function Tran(ByVal m As Integer, ByVal r As Integer) As String
Dim StrDtoR As String, n As Integer
Do While m <> o
n = m Mod r
m = m r
If n > 9 Then
StrDtoR = Chr(65 + n - 10) & StrDtoR
Else
StrDtoR = n & StrDtoR
End If
Loop
Tran = StrDtoR
End Function

2) R(2-16)进制字符串转换为十进制正整数。
思路:R进制数每位数字乘以权值之和即为十进制数。
算法实现:
Private Function Tran(ByVal s As String, ByVal r As Integer) As integer
Dim n As Integer, dec As Integer
s = UCase(Trim(s))
For i% = 1 To Len(s)
If Mid(s, i, 1) >= "A" Then
n = Asc(Mid(s, i, 1)) - Asc("A") + 10
Else
n = Val(Mid(s, i, 1))
End If
dec = dec + n * r ^ (Len(s) - i)
Next i
Tran = dec
End Function

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解题技巧
进制转化的原理要清楚,同时编写代码时候要留意16进制中的A-F字符的处理。

2、实战练习

1) 补充代码(2002秋二(9))
本程序是把给定的二进制整数转换为八进制整数。
Private Sub Command1_Click()
Dim a As String, b As String, c As String
Dim L As Integer, m As Integer, n As Integer
a = InputBox("请输入一个二进制数", "输入框")
(1)
a = String(L, "0") & a
(2)
For m = 1 To n / 3
b = Mid(a, 3 * m - 2, 3)
(3)
Next m
Text1.Text = c
End Sub

Private Function zh(s As String) As String
Dim i As Integer, n As Integer, p As Integer
p = 1
For i = 2 To 0 Step -1
(4)
p = p + 1
Next i
zh = Str(n)
End Function

2) 补充代码(2001春二(7))
下面程序是把给定的16进制正整数转换为10进制数。
Option Explicit

Private Sub Form_Click()
Dim St As Integer, Dem As Long
St=InputBox("输入一个十六进制数")

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